#log dif solution

38 messages · Page 1 of 1 (latest)

rotund hawk
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There was no sol provided. Could someone show me how to do it?

tall crystalBOT
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rotund hawk
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Maybe I did something wrong in the differentiation?

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There’s just no way I’m going to get near that answer provided with what I’ve got

azure abyss
copper arrowBOT
azure abyss
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don't use '×' when you're dealing with variables

rotund hawk
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Alright

azure abyss
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cuz '×' can be confused with x

rotund hawk
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Yh I understand

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Usually use dots or brackets innit

azure abyss
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,calc derivative('log(sqrt(sin(x))/x)','x')

copper arrowBOT
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Result:

(x * cos(x) / 2 / sqrt(sin(x)) ^ 2 - 1) / x
azure abyss
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that's how u can self-check ur work

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or use wolfram alpha

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you can continue by simplifying the RHS a bit

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you see there's two denominators $\sqrt{\sin x}$

copper arrowBOT
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vin100

azure abyss
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in the given answer you see "cot". that should come out easily after the simplificatioin

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simplication*

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after that you can look at the LHS

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how to get "dy/dx" from "(dy/dx) / y"?

rotund hawk
azure abyss
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here we're not gonna plot graph so forget number 2 for the moment

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symbolic view can tell us some precise info

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but sometimes it can be so abstract to human mind that it losts us

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so we rephrase the math expressions in words. i.e. we switch to the verbal side a bit

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  • current LHS = implicit derivative / y
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  • target LHS: impliciat implicit derivative only
rotund hawk
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Are you doing a bsc? Cause your maths is insane man

azure abyss
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i grad a few yrs ago

rotund hawk
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I’ve done all the applications

azure abyss
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  • current LHS: implicit derivative divided by y
  • target LHS: implicit derivative
    it shld be obvious that we multiply current LHS by y to get target LHS