#How do you solve the Integral??????
wintry windBOT
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fast knot
An idea for a parametrisation is : $\ \left ( \begin{array}{c}t \ 2t^{\frac{2}{3}} \end{array} \right )$
then you get the arc length by : $\ \int_{1}^{8}\sqrt{\left(\frac{dx}{dt}\right)^2+\left (\frac{dy}{dt}\right)^2}dt$
frail copper
Could you just help me with how to solve
fast knot
maybe substitute : $\ z=x^{\frac{1}{3}}$
charred fernBOT
Ludwig
