#algebra
222 messages · Page 1 of 1 (latest)
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his method was the same as mine lol
he started by doing minus
and i dont know how you got Y
ok
i literally tried any possible way i dont know how you got y
its like if your making stuff up
Ok so this is what I said.
3x + 2y = 15.
10x - 4y = 2.
Add both.
13x -2y = 17.
13x = 17 + 2y.
And we get x = (17+2y)/13.
3x = 15 - 2y.
Here x = (15-2y)/3.
And 10x = 2 + 4y.
So x = (2+4y)/10.
We got three values for how x can be in y terms.
From there I hope you can solve for x.
@viral glacier I don't know what you are trying to do but most of the steps in your calculations won't get you any closer to the solution. Why don't you explain a bit more so @frosty wolf can see how to solve this type of question?
What do you mean?
We have 3 different values for x now.
We have x = (15-2y)/3 = (2+4y)/10 = (17+2y)/13.
Cross multiply.
30 = (15-2y)(2+4y).
It seems like you can't decide if you are going to solve the system by adding,substituting or setting two equations equal. Instead of that you do everything of that at once but can't find the value of x. You could have solves the system right in your first step by adding the first equation two times.
30 = 30 + 60y - 4y -8y^2.
Deriving three expressions is absolutely pointless and won't get you anywhere.
May I continue?
Actually you have a point.
3 isn't necessary.
I was going overboard with that.
The point is that your way of solving this system is not a good way to get a lot of points in a test. You have used methods to solve a system of equations but using three of them at once will only cause confusion.
im still very confused
Now you can continue. But please do it in a structured way so that a student can understand your solution and reproduce it in a test.
Schlaumau it seems you are better at teaching, I would recommend you doing that.
I have to go anyway.
Plus I can't explain well in this condition.
no
because i dropped off for 8 months
about that
and i lost allot
isnt this just x=2 and y=9/2 you just multiply the top equation by two, then add the two together for 16x=32 -> x=2 and then solve for y
It is.
exactly but why do you have to do 32
why 16 x 2
well you add the two equations together to cancel out one of the variables
its a lot easier when you only have to solve for one
@left owl do you think it is helpful when we are both talking at the same time?
16
bruh ok then i'll go
$$6x+4y=30$$
$$10x-4y=2$$
When solving a systems of equations we are allowed to add two equations to another. Our goal by doing that is to eliminate one of the variables so we are left with an equation in a single variable. Another thing we are allowed to do is that we can multiply a line by a constant factor.
ok
Schlaumau
Do you see what I have done here?
how
because
you got 6x and 4y
what do you do after anyways
i understand this
next step?
I just told you that we can add two equations by adding their left sides and setting that equal to the sum of their right sides. What would we get if we do that here?
If you don't know you can tell me
i dont know
reading text is more confusing
then someon talking so do it step by step
with me
By adding the left sides we get
$6x+4y+10y-4y$
yes after
where did you get 40 from
Schlaumau
Now 6x+10x=16x and 4y-4y=0 so the left side becomes 16x
but why 32
why do you double 16
thats whats confusing me
that's exactly where im stick
stuck
When we added the right sides here we got 30+2=32
I didn't just double the 16.
Did you learn how to solve linear equations?
$16x=32$
Schlaumau
Okay. When solving equations we are allowed to do the same operation on both sides of the equation. As an example here we are allowed to divide both sides by 16.
i dont know
Oh you actually don't?
After that we get $x=\frac{32}{16}=2$
Schlaumau
16x/16 = 32/16.
16x = 32.
how do i get to 4.5
We are now going to substitute our value of x in one of these equations
By choosing the first one we get $6\cdot2+4y=30$
Schlaumau
Do you understand that so far?
We know that 6x+4y=30
Schlaumau
Sure
how to get to y
idk how to get Y
after this
i devided 10 by 2 and 4 by 2
them
I see
2 devided by 2 wich gave 1
then
i put all of them
and i got the X answer
now how do i get Y
any idea?
You have to substitute the value you have found for x into one of the equations you already know
You wrote 5x-2y=1
yes
Now you know that x=2 so $5\cdot2-2y=1$
Schlaumau
$10-2y=1$
Schlaumau
Is everything clear so far?
what does the dot mean
$5\cdot2=10$
Schlaumau
"times"
By adding 2y to both sides here we get 10=2y+1
We now want to remove the 1 from the right side so we subtract one from both sides
After that we have 9=2y
so 10-1
Yes
Which number times two is equal to nine?
We divide both sides of the equation by two
so i do 9 devided by 2
so the answer is 4.5
That's how you get y.
thank you so much
holly
you dont understand
im stuck here for 3 hours
i was watching yt and even maths solving application
none helped
your the only one that helped me
thank you so much
if i need help can i ask you in the future?
You can ping me then. But I cant guarantee that im going to answer immediately. But there are many other competent helpers here who you can also ask.