#Calculus 2 Volumes, Average value and work
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Calculate this integral for the mean value of a function in a given interval [a,b]: $M = \frac{\int_{a}^{b}{f(x)dx}}{b-a}$
Bonsai
In your case it'll become: $M = \frac{\int_{0}^{1}{xe^x dx}}{1-0} = \int_{0}^{1}{xe^x dx}$
Bonsai