#Given f(x) = 3x2 _ 2x + 6, find the tangent line to f(x) atthe point (1, 7) in slope-intercept form
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The slope of a tangent line equals the derivative of the function
f(x) = 3x^2 - 2x + 6
f’(x) = 6x - 2
Slope of tangent line at x = 1 equals f’(1)
you can ask @tacit garnet to do that for you on #bot-cmd-latex using the command ,w tangent line y = ..., x = ?
for example
,w tangent line y = x^2 sin(x), x = 2