#Transformations

21 messages · Page 1 of 1 (latest)

vital sable
sleek sorrelBOT
#
  1. Wait patiently for a helper to come along.
  2. Once someone helps you, say thank you and close the thread with:
+close
  1. Feel free to nominate the person for helper of the week in #helper-nominations
  2. Do not ping the mods, unless someone is breaking the rules.
  3. If you're happy with the help you got here, and the server overall, you can contribute financially as well:
vital sable
#

I attempted to solve this on my own, but found that it was difficult to retrieve the factors in which the graph was stretched/compressed in

#

I was able to figure out that it is shifted 4 units left and 2 units down

#

but that's about as far as I got

#

I know the points have significance but say I did plug in the points/vertical and horizontal translations

#

in the formula f(x)=af(k(x-d))+c I would still be missing either a or k which means it wouldn't be solvable algebraically

cobalt pollen
#

quickly gonna clarify ive never learned translating cubics

so does a(x-h)^3-k work or not

#

like a cubic is just a parabola but slightly steeper and one side is flipped

vital sable
#

I don't think there's necessaraly a specific formula for cubics, it would probably be just the formula stated above with a cube as the exponent for (x-d)

cobalt pollen
#

why is it af

vital sable
#

the f doesn't really have any significance, it's more of a filler in the formula

#

I assume it means a at y

#

but I've never personally touched it

cobalt pollen
#

try a(x-h)^3-k ?

#

f(k(x-d) is just fk(x-d)

#

and you can just make fk one variable i suppose

vital sable
#

yikes, I get 3=-731a

vital sable
cobalt pollen
#

wait i just re-read the question they want you to say horizontal and vertical shifts as a number independently dont they