#Trig Max Min Value
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Factorise 3sinx out and apply AM GM inequality
so 3sinθ(4-3sinθ)
then (3sinθ)+(4-3sinθ)/2 ≥ √(3sinθ(4-3sinθ))
2 ≥ √(3sinθ(4-3sinθ))
4 ≥ 3sinθ(4-3sinθ) that's the maximum value right?
Yes
so for the minimum value
-1 ≤ sinθ ≤ 1
-3 ≤ 3sinθ ≤ 3
1 ≤ 4-3sinθ ≤ 7
-21 ≤ 3sinθ(4-3sinθ) ≤ 21
so the minimum value is -21 correct?
or is there another way to compute minimum value