#subspaces
15 messages · Page 1 of 1 (latest)
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[1,1,1] is in the set, but q[1,1,1] isnt for any non-integer real number
so it's not closed under scalar multiplication
yes it's a subset, but it doesnt meet all the conditions on being a subspace
oh wait so scalars can have decimals
R^3 is a real vector space
the scalars are R
and there most definitely exists real numbers that arent integer / multiplies an integer to get an integer
like 1/2[2,2,2] is in the set, but 1/2[1,1,1] isnt
the 1/2[1,1,1] not being in the set means it cant be closed under scaling
since the scaling map sends (1/2,[1,1,1]) to something outside the integer lattice