please help i dont understand this at all | Mathematics | Page 1

hollow wind Oct 5, 2023, 3:19 AM

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please help i tried this so many times but cant do it

sacred juncoBOT Oct 5, 2023, 3:19 AM

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hollow wind please help i tried this so many times but cant do it

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hollow wind Oct 5, 2023, 3:21 AM

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ignore the units i just forgot to do them

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bro i genuinely dont think its possible

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all the answers ive tried are wrong

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i even tried asking chatgpt for a clue on how to do it and it got it wrong aswell

harsh crypt Oct 5, 2023, 4:07 AM

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What the fuck kind of question is this 😭

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There's no reference, it just mentions he wants it to reach a certain length, and there's not many givens

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And it has a theta

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hm

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Is this physics?

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I know theta in physics is angular position

hollow wind Oct 5, 2023, 4:10 AM

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harsh crypt Is this physics?

yeah bro its physics but i dont understand

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its like

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i know im suppose to get the horizontal velocity and vertical velocity

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then probably do somethign with soh cah toa

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to get the angle and other swide

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buyt when i did that

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it was completely wrong

harsh crypt Oct 5, 2023, 4:11 AM

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Did you try graphing?

hollow wind Oct 5, 2023, 4:11 AM

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harsh crypt There's no reference, it just mentions he wants it to reach a certain length, an...

you can use kinematic equations to get all the variables

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graphing?

harsh crypt Oct 5, 2023, 4:11 AM

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Yeah idek atp

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I take calculus this is some devil shit right there

hollow wind Oct 5, 2023, 4:12 AM

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bro i havent even taken calc yet

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appearantly this is on the test

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tomorrow

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though

harsh crypt Oct 5, 2023, 4:12 AM

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Like it just tells you the student's hope and dreams of shooting a cannonball with a really bad sketch and a greek symbol 💀

hollow wind Oct 5, 2023, 4:12 AM

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lmfaooo

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i can show you the work i duid to get the horizontal variables and vertical variables

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maybe that might help?

harsh crypt Oct 5, 2023, 4:13 AM

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I mean the first question is asking the maximum point

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Oh wait no

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It's asking how long it was in the air?

hollow wind Oct 5, 2023, 4:13 AM

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yeah

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thats easy though

harsh crypt Oct 5, 2023, 4:13 AM

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Or the rate of change before it bounced

hollow wind Oct 5, 2023, 4:13 AM

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nah the time it was in the air

harsh crypt Oct 5, 2023, 4:13 AM

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Oh

hollow wind Oct 5, 2023, 4:14 AM

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like the time it was rising and the total flight time

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the total flight time is just rise time multiplied by 2

harsh crypt Oct 5, 2023, 4:14 AM

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Oh interesting

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And it's rising for

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First look 25.5m?

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so uh

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If you found either of those you could just

hollow wind Oct 5, 2023, 4:16 AM

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i found the rise time by doing

v2^2 = v1^2 +2ad (kinematic equation)

v2^2 = (0)^2 + 2 (9.81) (52)

v2^2 = sqrt of 1020

v2 = 31.94

finding T

t= delta V / acceleration

t= 31.94 / 9.81

t= 3.26

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3.26 multiplied by 2 = 6.5

harsh crypt Oct 5, 2023, 4:16 AM

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ft=rt*2 or ft/2=rt

hollow wind Oct 5, 2023, 4:16 AM

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its in m/s

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im canadian

harsh crypt Oct 5, 2023, 4:16 AM

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No flight time and rise time

hollow wind Oct 5, 2023, 4:17 AM

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oh yeah wait let me think

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d= (v1+v2/2) T

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or

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d= v1 T + 1/2 at^2

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or

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d= v2 t - 1/2 at^2

harsh crypt Oct 5, 2023, 4:17 AM

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I have this class next semester yippie

hollow wind Oct 5, 2023, 4:18 AM

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you know what v2 and v1 means right?

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nah its lowkey easy

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just this one question

hollow wind Oct 5, 2023, 4:19 AM

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harsh crypt ft=rt*2 or ft/2=rt

both work yeah

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but i did ft= rise time multiplied by 2

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just the trig part i dont understand

hollow wind Oct 5, 2023, 9:34 PM

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+c;pse

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+close

#please help i dont understand this at all