#Cardinality Proof

5 messages · Page 1 of 1 (latest)

steady boughBOT
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subtle basin
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as |A|=|B| then they have the same cardinality so I would have thought it was required that f: A->B is a bijection

compact ember
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If f is onto, then it is one-to-one

subtle basin
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oh I wrote it down wrong. its prove if f is not onto then f is not one to one