I need help on finding the inverse of this | Mathematics | Page 1

versed dove Sep 17, 2023, 8:19 PM

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lucid vaultBOT Sep 17, 2023, 8:19 PM

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versed dove

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versed dove Sep 17, 2023, 8:22 PM

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Oh hi again

untold quail Sep 17, 2023, 8:23 PM

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versed dove

I think you need to simplify all the terms

versed dove Sep 17, 2023, 8:23 PM

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Yeah

untold quail Sep 17, 2023, 8:23 PM

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versed dove Oh hi again

Hello

versed dove Sep 17, 2023, 8:23 PM

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But is too much

untold quail Sep 17, 2023, 8:23 PM

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First of all sum of 1/k^2=pi^2/6

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And the second to last term is 0 because if you differentiate with respect to x, X becomes a constant

versed dove Sep 17, 2023, 8:25 PM

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When is a constant is 0

untold quail Sep 17, 2023, 8:25 PM

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Yep

versed dove Sep 17, 2023, 8:25 PM

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Forgot about thst

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Let me think

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This is not my thing...

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Im trash

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😭

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My brain isn't braining

untold quail Sep 17, 2023, 8:30 PM

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versed dove Im trash

No your not, here it may seem hard because of the sheer amount of terms but most of the terms simplify

untold quail Sep 17, 2023, 8:30 PM

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versed dove My brain isn't braining

It happens sometime I can’t do basic multiplication lol

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What part don’t you understand ?

versed dove Sep 17, 2023, 8:32 PM

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Did you just simplified that monster to 1/k^2=pi^2/6 + 0

untold quail Sep 17, 2023, 8:33 PM

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Well the sum of 1/k^2 is equal to pi^2/6

versed dove Sep 17, 2023, 8:33 PM

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versed dove

This monster

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I tought it was harder

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Let's recap

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We got first term 1/k^2=pi^2/6

untold quail Sep 17, 2023, 8:34 PM

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Yes

versed dove Sep 17, 2023, 8:35 PM

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And the rest is 0

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Cause is a constant

untold quail Sep 17, 2023, 8:35 PM

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The last term yes

versed dove Sep 17, 2023, 8:35 PM

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untold quail And the second to last term is 0 because if you differentiate with respect to x,...

...

untold quail Sep 17, 2023, 8:36 PM

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Well Σ1/k^2 -pi^2/6=0

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So this with the last term gives you only the first term

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So F(X)= ∫(sin(pi/2e^-x)+1/2ln(x^2+1))dx

violet oar Sep 17, 2023, 8:38 PM

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untold quail And the second to last term is 0 because if you differentiate with respect to x,...

but

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X is not a constant

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it's f(X)

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you get a bunch of dX/dx

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i can only assume that the thing inside the d/dx is supposed to be x

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lowercase

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evaluated at x = 3

untold quail Sep 17, 2023, 8:39 PM

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Ohhh yes my bad my brain ai t functioning either

untold quail Sep 17, 2023, 8:41 PM

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violet oar i can only assume that the thing inside the d/dx is supposed to be x

Umm u sure it’s X uppercase no ?

violet oar Sep 17, 2023, 8:41 PM

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uhhh but the integral is not elementarily integrable

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i kinda like the 0 theory

untold quail Sep 17, 2023, 8:41 PM

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violet oar uhhh but the integral is not elementarily integrable

i agree lol

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If it were from 0 to infinity it would’ve been the Gaussian integral but here it’s not possible without a calculator I think

violet oar Sep 17, 2023, 8:42 PM

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except the fact that it's f(X) bla bla bla evaluated at X = 3 makes me think all the uppercase X's in that part of the eqn are supposed to be lowercase

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you can use erf

untold quail Sep 17, 2023, 8:43 PM

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Yeah

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Dam this is annoying

versed dove Sep 17, 2023, 9:40 PM

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@violet oar

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So?

violet oar Sep 17, 2023, 9:40 PM

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so?

versed dove Sep 17, 2023, 9:40 PM

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Sorry for ping

violet oar Sep 17, 2023, 9:40 PM

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i guess just go with the 0 theory

violet oar Sep 17, 2023, 9:40 PM

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untold quail So F(X)= ∫(sin(pi/2e^-x)+1/2ln(x^2+1))dx

so then you would integrate this

versed dove Sep 17, 2023, 9:40 PM

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Ok

violet oar Sep 17, 2023, 9:41 PM

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but wait, that's a constant, then

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constants don't have inverses
what is this question

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badly written question at best

versed dove Sep 17, 2023, 9:41 PM

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Yeah

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Let me find it

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(1/2)ln(x^2+1)x - (2/3)x^3 + C2

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That should be the integration

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I think i got bamboozeled

untold quail Sep 17, 2023, 9:45 PM

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violet oar but wait, that's a constant, then

Yeah that’s what I was thinking

versed dove Sep 17, 2023, 9:46 PM

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Alr so its possible to answer

violet oar Sep 17, 2023, 9:46 PM

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i don't think so

untold quail Sep 17, 2023, 9:47 PM

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Well from what is presented yes

versed dove Sep 17, 2023, 9:47 PM

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versed dove (1/2)ln(x^2+1)x - (2/3)x^3 + C2

Is this correct?

violet oar Sep 17, 2023, 9:47 PM

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from what is presented, the answer would be "no inverse exists"

versed dove Sep 17, 2023, 9:47 PM

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violet oar from what is presented, the answer would be "no inverse exists"

Ok

violet oar Sep 17, 2023, 9:47 PM

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versed dove (1/2)ln(x^2+1)x - (2/3)x^3 + C2

it's definite integral, no constant

untold quail Sep 17, 2023, 9:48 PM

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Alr well I’m going to sleep gn y’all

versed dove Sep 17, 2023, 9:48 PM

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versed dove Sep 17, 2023, 9:48 PM

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versed dove

@violet oar

violet oar Sep 17, 2023, 9:49 PM

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someone just invented that, yep

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the giveaway is the 1/n^2 - pi^2/6

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0 point in putting that there, just makes it look more confusing

#I need help on finding the inverse of this