#Been asked to solve cubic root of (729)
47 messages · Page 1 of 1 (latest)
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Note: tartaglia's formula doesn't seem to help
or just prime factorize 729…?
No
...no
???
Do you want the complex solutions as well ?
Yeah
I want the work out
Like a tip
Or something
Ok
Do you know how to solve the third roots of the unit ?
Not the complex numbers
I really strugle with those
Hmmm well 1= e^(2kipi)
-9i isnt an answer right?
Nope
Give me only 1 tip
All the solutions of z^3=1 are of the form e^(2kipi/3) with k in{0,1,2}
Alr so
Also the cubic root of something is unique you should’ve said solve the equation x^3=729
1, (e^{(2i\pi/3)}), and (e^{(4i\pi/3)}).
/🤍Byte Benders🤍™/ Katie
?
Yes !
And e^(4ipi/3) is the conjugate of e^(2ipi/3)
Yes 1=x/9, e^(2ipi/3)=x/9 or e^(4ipi/3)=x/9
Thanks you too !