Could someone help me with this project?

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[zenith ermine]

5 and 6 are quite similar tbh

wait wait your formula is slightly wrong you said there’s 100 ppl on hour 1 however when I find hour 1 in your formula I get 100(2^1) which is 200

easy fix tho dw

q3, general formula

doesn’t match up with your answer to q2

try calculating how many people are in the 1st hour

well you try figuring it out it’s a nice problem solving exercise

hint can you chance the constant so x(2^1) is 100?

n?

no n is your hours

that needs to remain a variable

well you need to find c(2)=100

where is a constant

and the 2 came from 2^1 which is # of people in the first hour

2c=100

c=?

a constant

it was 100 in your equation

but we want a c that satisfies the first hour thing

yup

so your new equation for the # of people could be?

yes

and see if it works for your first hour thing

50

well it doesnt work for your value of hour 1

so you need it to work for your value of hour 1

100 also works if you make it $100(2^{n-1})$ but that just looks worse imo

[hard agate]

!𒐪 ɹɐupoɯ⇂ㄥ8𝟝 𒐪!

[zenith ermine]

it is increasing geometrically yes

50(2^n) is also inscreasing geometrically

but it increases geometrically at a rate of doubling per hour

it cant go from 100 hour 1 to 400 hour 2

acutally you could just

say 200 is hour 1

then you dont have to change anything

100 times 4 is 400

the rate is times 2 an hour

nono c is the starting value (hour 0)

2^n is your increasing rate

It makes sense for the stadium to go from 100 to 400 in an hour if it’s increasing geometrically.
100 to 400 means your common ratio is 4 as ive said your common ratio is 2 and that doesnt work

i mean tbh if your teacher did tell you 100 was the forced value of that

well you would have to modify your euqation to account for that

because currently your equation here doesnt account for the 100 theres a disagreement

well it shoudl be

however if you plug in a_1 into your equation you end up wtih 100(2^1) 100(2) 200

nono so

2^n

and for a_1 we substitute n for 1

right as thats how we find terms of the sequence

i mean you have the method

youve understood the concepts of the questions

all you need to do is change some numbers around