#Help

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obtuse plankBOT
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crude jewel
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okay note that there can only be 0 to 2 heads, that should greatly simplify it

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idk if there’s a better way from there or if you just lost everything

cunning flicker
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ik that but do i have to list everyoutcome

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or do i generalize

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and i do not know how to generalize

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like i know if the probabillity that k=0 would be 1/4 *1 since the probabllity of 0 could only be derived from getting 0 heads which is 1/4 times every possible dice roll prob which adds to 1

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for k =1 it would be 0 since the smallest sum of dice is 2

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but it says 0,1,2,3...

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so how many more products do i do?

crude jewel
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well find the maximum possible value and check everything below it

cunning flicker
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How would I find the maximum?

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Is it 24?

crude jewel
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yea

cunning flicker
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So I have to find 24 products?

crude jewel
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note the number of dots is just sum of the dice numbers

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so you can find odds of sum numbers

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then multiply by coin

cunning flicker
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Odds of sum numbers? Wym

crude jewel
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the odds of the dice summing to something

cunning flicker
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Bro I know that

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Wait nvm

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You mean like

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Idk can you give me an example

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So you mean like 1/4 times odds of sum over 36

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Or like 1/2 times odds of sun

crude jewel
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so once you’re done your probability table for like all the dice just combine it with the heads to find all your possible values

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then do a ton of arithmetic

cunning flicker
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Uhh what does that mean?

crude jewel
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okay so the odds of rolling a 7 is 1/6 (1,6 2,5 … 6,1)
and then we can pair it with one head (1/2) to get a value of 7 with odds 1/12 and a value of 14 with odds 1/24 and so forth

cunning flicker
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7 with odds 1/12?

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How did you get 1/12

crude jewel
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7 (dice) (1/6)
with
1 (head) (1/2)

cunning flicker
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Ok how did you get 1/6

crude jewel
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oh so there’s 6 ways to get a sum of 7

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1,6 2,5 3,4 4,3 5,2 6,1

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and 36 possible combinations of the two dice (6*6)

cunning flicker
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Oh ok

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Yea

crude jewel
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and you can find the odds for sums 2-12

cunning flicker
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You’re saying if I do that I think can get the odds for sums- 12-24 by multiplying denominator by 2?

crude jewel
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well no

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so my idea was

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the dice can sum to 2 to 12 right

cunning flicker
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Yea

crude jewel
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and then the heads are either 1 or 2

cunning flicker
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Yea

crude jewel
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so you have 1*2 1*3 … as possible values and also 2*2 2*3…

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and some values appear twice in that

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and you can find the probability of each like

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little case

cunning flicker
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Ok I lost you there

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12 13?

crude jewel
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so we have 1 head

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and the dice rolled sum to 2 or 3

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the like product of both is 1*2 1*3

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and it has a specific probability too

cunning flicker
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The like product ?

crude jewel
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well your question wants the odds the product of the number of heads and the number of dice dots

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is a specific integer

cunning flicker
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can you give me the one for k= 3 and k=4

cunning flicker
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?