#Real Analysis: Proving this series is divergent
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Hmmm well the way I’d do it is study all the possible cases:
Case1: the sequence an diverges than the series an/(1+an) diverges because it doesn’t have a null limit
Case 2: an converges to a non 0 limit , so an/1+an also converges to an non 0 limit thus the series diverges
Case 3: an converges to 0 than an/(an/(1+an)=1+an
Knowing an converges to 0 we have an~(an((1+an)) but the series an diverges thus the series an/(1+an) diverges as well
I think this is a way to do it but not sure