Help on Complex Numbers Problem

[spark kite]

How exactly do I solve this problem? It’s unlike the previous problems I’ve encountered in this chapter.

[grave trout]

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[cedar quarry]

Yoo yo yo my homeslice
So the thing u gots to do is solve for x first
Once youse got a solution for x in complex nos just convert it to polar and cartesian ong

So here you gots x^6-1=0

Soooo
x^6=1
Which means all the sixth roots of unity

Now the most basic ones are $x=1$ and $x=-1$

The rest have to be forms of $-1$

So you have $\pm(-1)^(1/3)$ and $\pm (-1)^{2/3}$

Now ur a smart dude so u can convert to polar form I'm sure if u need help doe just ask

[timid bone]

beethobeanie

[cedar quarry]

Now Brodie the easiest way to solve these problems is using exponential notation for complex nos just lmk if u know what that is or nah can explain accordingly

[raw hazel]

nah

basically

you just factor it

use difference of squaares

and then do difference/sum of cubes

then its ez

[spark kite]

Is that (+/-)(1/3) or (+/-)^(1/3) ? How do I get that?

[spark kite]

Alright. I got it thanks.

+close

[grave trout]

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