#Logarithm problem
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So I assume it’s solve the SOE
For top equation, use the fact that ln(a)^b = b • ln(a) and vice versa
So ln(y) = -4 • ln(x+1) or 1/ln(x+1)^4
sorry but what does it means
Well, no. ln(a^b) = b ln(a). ln(a)^b does not.
Ln(a)^b can mean ln(a^b) not specifically ln^b(a)
no it means here
ln[(x+1)^4]
so 4ln(x+1)
But i Can't find the solution i tried to simplify it by assuming lny= 4lnx+1
it gives anything
...missed a negative.
If you we assume here ln(a^b)= bln(a) you can express x in term of y on the second line
Using the properties of ln
Then you can substitute on the first line and solve for one of the variables
Yeah its missed it when i wrote it on discord put i puuted it in my calculus
You also missed parentheses.
heres de problem when a substitute one the other line to solve it i dk how to do it i get this (the picture is comming)
WoW that looks annoying
Well you could write x=x+1-1
Then develop ((x+1)-1)(x+1)^4=(x+1)^5-(x+1)^4
Let X=x+1
Then you need to solve X^5-X^4=1
Find the roots of X^5-X^4-1
Not all of the roots because note that logarithms are involved so you need x>0 and x+1>1 thus X>1
Also this polynomial doesn’t have any rational roots
There is only 1 solution on the interval ]1,2]