Calculus | Mathematics | Page 1

plush wyvernBOT Aug 3, 2023, 9:12 PM

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main raft Aug 4, 2023, 1:06 AM

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So wait why are you differentiating the thin lens formula @humble scarab

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I’ve done optics before (I didn’t go really in depth) but I’ve never seen this before

main raft Aug 4, 2023, 11:28 AM

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OHHHHH

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I REMEMBER THIS

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Sorry I feel asleep and just woke up

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Also I’ve been doing QM and forgot half of optics lmao 💀💀💀

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Ok so if I recall correctly

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Alright basically

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MsubL=Δx2/Δx1

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Whereas

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MsubT=Y2/Y1 = -S2/S1

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yk what here

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https://physics.stackexchange.com/questions/470338/longitudinal-magnification

Physics Stack Exchange

Longitudinal magnification

I want to prove that if an object is small in length and lying along the principal axis then
$$M = -\frac{dv}{du} = -\left(\frac{v}{u}\right)^2$$
Where, $M$ is the longitudinal magnification.

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go to this artical

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it proves the thing you are asking for, since I don't want to, write the entire derivation

main raft Aug 4, 2023, 12:59 PM

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@humble scarab

main raft Aug 4, 2023, 4:29 PM

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Which part the writing or the equation?

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It’s saying the derivative (change in) of 1/u+1/v remains constant

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Oh I see what your question is

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It’s like

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Lemme think of a way to explain this

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Oh

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So 1/u and 1/v are constants right?

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Assuming no variation in 1/u and 1/v

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They are constants

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If we assume no variation, so the derivative (which is seeing the change in an object) of the sum of these 2 constants is 0

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Since we are saying they cannot change

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We are defining their exact position

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it makes sense now right?

#Calculus