#integral with inverse trig
6 messages · Page 1 of 1 (latest)
- Wait patiently for a helper to come along.
- Once someone helps you, say thank you and close the thread with:
+close
- Feel free to nominate the person for helper of the week in #helper-nominations
- Do not ping the mods, unless someone is breaking the rules.
- If you're happy with the help you got here, and the server overall, you can contribute financially as well:
veganmf
veganmf
Hm, let's see. We have:
tan(arctan(x) - arctan(2x)) = (x - 2x)/(1 + x(2x)) = -x/(1 + 2x^2)
So, the expression under the integral is -dx/(1 + 2x^2), which integrates to -π/(2√(2)) = -√(2)π/4. So yeah, correct.
@snow thorn has given 1 rep to @neon valley