polynomials question

[signal sparrow]

Test cases: When $Q(x)=0$, either $2x-k=0$ or $P(x)=0$. When $Q(x)>0$, $(2x-k)$ and $P(x)$ have the same sign.

[royal marten]

civil_service_pigeon

[heady spindle]

@wild comet

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