#Pls do my math hw
13 messages · Page 1 of 1 (latest)
That is enough for 4
For 5 just plug x=1, p(x) = 0 and solve for a
- Suppose you have two numbers a and b that satisfies this condition
A = 18m, B= 18n, where m and n are integers
LCM(A,B) = AB / HCF(A,B)
AB = 380•18
mn = 380•18/18/18
mn = 380/18
mn = 21.111111
Can two integers equal a non-integer?
- Again, two numbers a and b such at ab = -1/2 and a+b = -3/2sqrt(5)
Hint: Have a and b in the form of m/2sqrt(5)
- Represent the two digit num as 10a+b, so the number is ab (digits, not multiply)
10a + b = 8a + 8b - 5 = 16a - 16b + 3
- Angles of triangle add up to 180
x+y = 140
x - y = 20 as given
- you have A and B people in each hall, sending twenty students from B to A means A is now double B, or A + 20 = 2B - 40
Sending 10 from A to B makes it equal, or A-10 = B+10