#A quick question...

16 messages · Page 1 of 1 (latest)

elfin topazBOT
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vernal shadow
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do you have any idea where to start?

thorn bay
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Is it sqrt(5/2) or sqrt(5)/2 ?

vernal shadow
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well you need some factor of sqrt 5 to cancel out the 3(sqrt5), but you also need a perfect square as a factor so the 2 doesnt have a sqrt

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try to find from here

thorn bay
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You can use surds perhaps?

vernal shadow
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actually

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just use difference of squares

thorn bay
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Find the squares of 3 and multiply it with 5. Make sure to draw the sqrt symbol on it

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Sqrt(45)

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Eugh that's irrational

vernal shadow
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difference of squares easiest way

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if you know what that is

vast ocean
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to rationalize denominator multiply by the conjugate, that is, to remove a + b*sqrt(c) from the denominator, multiply it and the numerator by a - b*sqrt(c)