#Factoring Help
112 messages · Page 1 of 1 (latest)
I've never been shown an example of this expression with a fraction before
would it technically just be 4 or -4? I'm not sure
wdym
I'm not sure, like the reciprocal of it or something but I'm just not sure how to use a fraction in this situation
well if x^2 = 1/4 what is x
not considering the negative value
btw the top right one you selected is right
try the different values you see for the coefficient of x
is 1/2 * 1/2 = 1/4
is 1/4 * 1/4 = 1/4
since 64 is a square we can be pretty sure to factor it like that
1/2*1/2 = 1/4
can I show u the work I have so far for it aswell?
ok
so we have
(1/2x+b)^2
we know b = -8 or 8
since b^2 = 64
but since 2ab is negative
which one is it?
-16 = b
2 * 1/2 = 1
1*b = -8
then just write it in the form
(a+b)^2
and see which answer that matches
ohhhhhh this is different, I was doing a different format
oops
let me try that
the top answer?
cool ty
so am I trying to find the gcf? and turn this equation into two binomials?
I'm not sure what two numbers can multiply and get to 90 and add to get to -19
cuz I'm trying to find m+n and m*n, no?
-10
ok
ok
since the 10 and 9 add together we want them together
I'm gonna switch the 9 and 10
since if they are seperate then will multiply
there's no number besides one that can go into 9 and 10 hmm
assuming the non x values are negative
if -10 * something = 10
what is that something
1
-1
ok and 9x * what = 9x^2
so I would just multiply them by one?
which factored form has all those numbers as coefficients
yes
for the next one ac = 3 and b = 4
basically the roots multiply to 3 and add to 4
so what are they?
I'm lost 😠sorry, I'll figure this out eventually
well
I think it's the bottom answer
1 and 3
(x+3)(x+1)
last one is rhe same thing huh
basically
since c is positive and b is negative
we can assume both numbers we are looking for are negative
so the 2 numbers multipled = 4
and they are both negative
there are only 2 integer sets for this
can you list them?
(x-4)(x-1)
yea
or x,4,x,-1
cool ty!
thanks for being patient with me I appreciate your help
np