im struggling to grasp this concept. can someone help and explain to me how to do this ?
I know a little bit of what to do, just need some help
#struggling
regal tartan
would the first one be 2x^2 + 64 + 36 ?
viscid sandal
would the first one be 2x^2 + 64 + 36 ?
No.
A perfect square trinomial should be representable as a(x - x0)^2 for some constants a and x0. So, complete the square in all of them.
regal tartan
I'll tryy
im so lost
I have notes but im not sure how to use them and figure this out
im thinking it's x^2-2x+2 because the equation for the right is (x+b/2)^2
viscid sandal
im thinking it's x^2-2x+2 because the equation for the right is (x+b/2)^2
No.
As I said, complete the squares first.
regal tartan
the last one?
viscid sandal
Yes.
regal tartan
okay cool cool
are u able to help with the other questions?
viscid sandal
Sure.
For the second one, solve the equation x^2 + 18x + 81 = 0. Then if you get roots x = a and x = b, then the factorisation will be (x - a)(x - b).
Same approach for the third one.
regal tartan
okay cool, thank you! I'll try my best lol
viscid sandal
Good luck!
regal tartan
for the second equation, there's no exponent that could multiply by itself to = 18?
i don't know what to do for thst
viscid sandal
If you can't use Vieta's formulas, use the quadratic formula. Or complete the square.
viscid sandal
for the second equation, there's no exponent that could multiply by itself to =...
The correct way to use Vieta here would be:
x1 + x2 = -18
x1 x2 = 81
regal tartan
ive never heard of vista's formula before huh
vietas
i got the answer (1x+9)^2
how do I write that as the product of two binomials
viscid sandal
i got the answer (1x+9)^2
how do I write that as the product of two binomials
Well, obviously, (x + 9)(x + 9).
regal tartan
Isn't that what you were trying to use, though? Oh well.
that makes sense sorry thank u for helping!
ashen foxBOT
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