#Problem in exam
256 messages ยท Page 1 of 1 (latest)
exam? sus
is this an exam?
if you notice that ABD ~ DBC
well ABD ~ ADC ~ DBC and similarity is transitive
if you just call some length here x then you can most likely use proportionalities and pythag to solve for x
I don't think ABD and DBC share any similarities with each other because they're not an isosceles triangle
Wdym right
angle
B has a right angle, so does D
But not the line that cuts through D
The line that cuts through D has a right angle on B
We've not done this before
weird that it was on the exam, then
prove the triangles similar then use similarity to find sides
^
I don't understand
prove that the 3 triangles in the diagram are similar?
I don't go to an English school what does similar mean
they are in fact similar
to prove similarity you just need 2 same angles
the right angle is 1 of them
wha
No
look at the medium triangle and the big triangle
they both have angle A
The medium triangle is ABD and the big one is ACD?
yes
you dont
just notice that they both have it as their angle
they are also both right triangles
so ABD is similar to ADC
you can run the same justification with the small triangle and the big triangle
.
so this will most likely convince you that all the triangles are similar
now you can use proportional sides
remember that we called BD x and AD = sqrt(64 + x^2)
you know that the legs of ABD are in the same ratio as the legs of ADC
yes it looks like there's a simpler way
Yeah?
well I was thinking AB/BD = AD/CD
wdym
8/x = sqrt(64+xx)/3
this is definitely getting ugly
Still stuck lmao
i got some weird stuff
Why 8/x?
that is in fact what i said in the message i replied to
oh
I'm dumb
Fuck
Where does the sqrt(64+xx) come from
Shouldn't it be 8/x = AD/3
cuz we defined AD as sqrt (x^2 + 64)
Ahhhh
My lack of sleep is showing
Is the equation correct?
What did I do wrong?
you didnt do sqrt of (x^2+64)
and you also didnt distribute the x to the 64
in that scenario
What does the sqrt of (x^2+64) do
The value of AD is 64 + x^2
Wait
Ur right
Now?
The both Xs right
Or you have to multiply both by x^2
AD is in sqrt
BD is not
So when you multiply
You either transfer the x inside the sqrt and do sqrt(x^2)(64 + x^2)
Or
You keep the x outside and do x * sqrt (x^2 + 64)
So like this
I got a question
So in an equation
When you multiply something does it apply to everything or only once per side
like, if you have a = bc
then 2a is not (2b)(2c)
it's 2bc
once per side
however if you have addition a = b + c
then you would multiply everything
2a = 2b + 2c
Makes sense
My stupid ass
How difficult is this question
For college mathematics
Even tho I'm in HS
๐
Assuming your HS taught you how to prove triangles are similar and factor expressions
Interesting
Might've missed a class or two
You should get taught in geometry
This is the first time I was doing this problem
Yeah we have geometry
Not this shit tho
Could I just do -64 to bring it to the left
I would square it
So, 8+X?
To get rid of square roots so
Help
(24)^2 = x^2 (64 + x^2)
Since square roots are taking it to power of 1/2
We want power of one
So we take to the power of 2 to do that
i already said that lol
there's also sqrt(a^2) = a^2^(1/2) = ??? somehow absolute value gets introduced = |a|
I gotta take a moment to understand this
Now i did
I don't understand this
Just remember that taking the square of a square root cancels the square root
Is taking the square root calculating it
Wdym
Yea
But for things that canโt be simplified that easily
Sqrt(x) = Sqrt(73)
Squaring both sides
x = 73
Yeap
But what is this?
How else would you solve something that has a โ in it?
Other than to, cancel it
Could you do รท โ?
And you're left with a
So 4 = โ9X / รท โ
โ4 = 9X
square root is not dividable like that
it's a function
not a number
that makes as much sense as dividing by +
I thought you meant sqrt (a)
So what is the correct way to bring it to the other side
wdym by bring it to the other side
So for the example 4 = โ9X what do i have to do to get โ4 = 9X
Thatโs not equal
If itโs over only the 9
If it's over both?
3 * โX?
Yea
Damn aight
I'm pretty dum
Well thanks for the help guys
I wish to improve my math ๐
You are all good?
๐
I got another question
So if I have ab + 7 = 7a + b
And i multiply by 2
Is it 2ab + 14 + 14a + 2b
2ab + 14 = 14a + 2b
Yeah so by everything
Yea
Yea
Np
+close