#find the derivative of the following function.

39 messages · Page 1 of 1 (latest)

queen crow
lofty wedge
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Product rule (uv)' = u'v + uv'

queen crow
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i did that the math algebra part of it is what i am stuck on

lofty wedge
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u=x^2 and v=(x-3)^4

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tell me what u' and v' are

queen crow
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i got x^2*4(x-3)^3+(x-3)^4(2x)

lofty wedge
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that is correct

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if you wanna be fancy you can also factor

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$y' = 2(x-3)^3 (2x^2 + x(x-3))$

cosmic vaporBOT
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al8628

lofty wedge
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$y'=6x(x-3)^3(x-1)$

cosmic vaporBOT
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al8628

lofty wedge
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but this should not be necessary

noble verge
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Not this again

queen crow
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i am stuck x^2*4(x-3)^3+(x-3)^4(2x) how do i factor it out

lofty wedge
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it's not necessary

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this is the initial problem

queen crow
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my teacher wanted to apply the algebra once you find the derivate that why i came here

lofty wedge
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that is not written in the problem statement and I am not clairvoyant

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you should formulate your question more precisely

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if the above is not sufficient

noble verge
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You did so much algebra trying to find the derivative using the definition and you find trouble on this?? Lol. Just factor out x(x-3)^3

lofty wedge
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Don't bully, please

noble verge
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@queen crow do you feel bullied?

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@lofty wedge eh bullying works. Traumatic experiences stick with us longer

lofty wedge
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fair play

queen crow
lofty wedge
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what does applying algebra mean?

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are you talking about collecting common factors?

queen crow
lofty wedge
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alright, I have written 2 versions of the factoring above, do you understand why they turned out like this?

noble verge
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@queen crow yeah i will give you that there was no factorisation there only long expansion.

lofty wedge
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well, this is as elementary as it gets, do tell what the problem is

queen crow
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i will take a picture of what i am doing and what i am getting stuck on here

noble verge
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@queen crow still tho the factorisation here should be obvious. If not you maybe need to do many factorisation examples so you are comfortable with it.

queen crow
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i think i figured it out