#find the derivative of the following function.
39 messages · Page 1 of 1 (latest)
Product rule (uv)' = u'v + uv'
i did that the math algebra part of it is what i am stuck on
i got x^2*4(x-3)^3+(x-3)^4(2x)
that is correct
if you wanna be fancy you can also factor
$y' = 2(x-3)^3 (2x^2 + x(x-3))$
al8628
$y'=6x(x-3)^3(x-1)$
al8628
but this should not be necessary
Not this again
i am stuck x^2*4(x-3)^3+(x-3)^4(2x) how do i factor it out
my teacher wanted to apply the algebra once you find the derivate that why i came here
that is not written in the problem statement and I am not clairvoyant
you should formulate your question more precisely
if the above is not sufficient
You did so much algebra trying to find the derivative using the definition and you find trouble on this?? Lol. Just factor out x(x-3)^3
Don't bully, please
@queen crow do you feel bullied?
@lofty wedge eh bullying works. Traumatic experiences stick with us longer
fair play
i didn't apply algebra when i was doing the derivative i just know the formula but after doing it, the algebra part is what i am stuck with
yes i grouped it as doing the alegbra
alright, I have written 2 versions of the factoring above, do you understand why they turned out like this?
@queen crow yeah i will give you that there was no factorisation there only long expansion.
no
well, this is as elementary as it gets, do tell what the problem is
i will take a picture of what i am doing and what i am getting stuck on here
yes
@queen crow still tho the factorisation here should be obvious. If not you maybe need to do many factorisation examples so you are comfortable with it.
i think i figured it out