#how do i get the values in terms of n?

54 messages · Page 1 of 1 (latest)

tranquil pier
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can some explain? thanks

fading cedar
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firstly

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what is the constant

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what stays the same

tranquil pier
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60?

fading cedar
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yes

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so that will still be 60

tranquil pier
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wait, so do i just continue what i already did essentially?

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because i dont really understand how to give the value in terms of n itself

fading cedar
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the first term =

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110

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she sprinted 50 meters

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next time she sprinted

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100

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then 150

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can you see a pattern?

tranquil pier
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yeah i get that part

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but like yk near the end

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sec

fading cedar
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60 + 50(?) = 110

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60 + 50(?) = 160

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can you solve the question marks

tranquil pier
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1, 2

fading cedar
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yea

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so 60 + 50(1) and 60 + 50(2)

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are the 1st and 2nd terms

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meaning 60 + 50(n) will be the

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?

tranquil pier
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nth term?

fading cedar
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yup

tranquil pier
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or value

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so for the last row would it be 60, 50(n), 110(n)?

fading cedar
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no

tranquil pier
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oh oops

fading cedar
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50n is correct

tranquil pier
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not the last part

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yeah i realized now

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would you just say 110 for the last bit

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right

fading cedar
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no

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...

tranquil pier
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or would it be different since the value is changing

fading cedar
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just add the two terms

tranquil pier
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oh

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i think i understand now lmao

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is the question trying to get me to do the last row but do it in terms of n?

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so like

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60 + 50(6) = 360

fading cedar
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yes

tranquil pier
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ahhhh

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got it

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appreciate it

fading cedar
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np

tranquil pier
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it sounded way harder than it really was