#Calculus

22 messages · Page 1 of 1 (latest)

rigid horizon
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do you have any ideas on how you might do this?

mossy hill
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idk them asking for the tangent line throws me off alot

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would i need to fine the derivative first or use some rule?

rigid horizon
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the slope of the tangent line = the derivative

mossy hill
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Oh

rigid horizon
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(that's sort of what the derivative means)

mossy hill
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would it look like this?

rigid horizon
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what's the derivative of x?

mossy hill
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I dont know

rigid horizon
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just d/dx x

mossy hill
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was what i wrote wrong ?

rigid horizon
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bear with me for a second

mossy hill
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ok

rigid horizon
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find
[\frac{d}{dx} x]
and, using the method you just used,
[\frac{d}{dx} \frac{x^2}{x}]

lime heartBOT
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Invariance

mossy hill
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d/dx confuses me I dont really understand what your asking me to do

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like how would i go about plluging that in ?

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sorry

rigid horizon
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that means the derivative

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d/dx [something] means "the derivative of [something] with respect to x"

mossy hill
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hold on