#How would I go about solving this?
6 messages · Page 1 of 1 (latest)
= 1
There are possible values of E
That are different numbers, but equal to the same value
So there's basically two steps to this. Step one is figuring out the value(s) of E. Step two is actually performing the sum. Both are relatively easy to do in calculus.
Hint: let
[S = 1 + \varepsilon + \ldots + \varepsilon^{2023} .]
Then
[\varepsilon S = \varepsilon+ \ldots + \varepsilon^{2024} ]
and also
[S - 1 + \varepsilon^{2024} = \varepsilon+ \ldots + \varepsilon^{2024} ]