#Math problem car weight distributin
63 messages · Page 1 of 1 (latest)
What is the total weight if you remove 30kg?
@pure kestrel
1917.5kg
It just asked how much needs to be changed
So just the absolute difference of the original from now
Yes
So removing 30kg in the back and adding 4.6 to the front would keep it 60-40?
40%
To maintain the weight distribution of 60% in the back after removing 30 kg, we can set up the following equation:
(1185.1 kg - 30 kg) / (1947.5 kg - 30 kg) = 0.6
Simplifying this equation:
1155.1 kg / 1917.5 kg = 0.6
Now, let's calculate the weight that needs to be removed from the front.
Let x be the weight to be removed from the front.
762.4 kg - x kg = 0.4 * (1917.5 kg - 30 kg)
Simplifying this equation:
762.4 kg - x kg = 0.4 * 1887.5 kg
762.4 kg - x kg = 754.5 kg
x kg = 762.4 kg - 754.5 kg
x kg = 7.9 kg
Therefore, you need to remove 30 kg from the back and 7.9 kg from the front to maintain a 60% weight distribution in the back.
Chatgpt says otherwise
Why is it 1917.5 - 30
You took 2/5 of 1887.5
You have 60.9 percent currently
Assuming I removed 30kg from the back it becomes 1155.1kg
So how can 60% of 1917.5 be 1150.5kg
something isnt making sense
1917.5 x 0.6 = 1150.5
That’s not how it works
You can’t subtract from both sides to maintain a constant ratio
It’s like saying
8/1
= 8-4/1-4
= -4/3
Is 8 equal to -4/3?
So I had to add 4.6kg to the front.
Remove 30kg from the back.
Which resulted in 60% in the back and 40% in the front.
Not true
You need to remove
More
From the back
Whatever you are adding to the front
0.39760104302
Wiat
Wait
It doesnt matter
aslong as its 60% in the back
I dont have to do anything right?
Aslong as its 60% and upwards its fine
Right now 60.24
So in the back its 60.24%
Is approx on the back