#Math problem car weight distributin

63 messages · Page 1 of 1 (latest)

pure kestrel
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A car weighs 1947.5kg total, in the back it weighs 1185.1kg, in the front it weighs 762.4.

The front weighs 39.1% and the back weighs 60.9%.

To pass inspection my car needs 30kg removed but it needs to maintain 60% in the back and 40% in the front. How much weight has to be changed in the front?

burnt pumice
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What is the total weight if you remove 30kg?

burnt pumice
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@pure kestrel

pure kestrel
burnt pumice
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Ok

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Now we want 40% in the front

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What is 40% of that

pure kestrel
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So adding weight is the answer?

burnt pumice
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It just asked how much needs to be changed

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So just the absolute difference of the original from now

pure kestrel
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Oh

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1947.5 - 30kg
1917.5 * 0.4 = 767
767 - 762.4 = 4.6kg

burnt pumice
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Yes

pure kestrel
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So removing 30kg in the back and adding 4.6 to the front would keep it 60-40?

burnt pumice
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Well that’s 40%

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Do u need 40 % or do u need to maintain 39.1%

pure kestrel
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40%

burnt pumice
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Yea

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So that is your answer

pure kestrel
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To maintain the weight distribution of 60% in the back after removing 30 kg, we can set up the following equation:

(1185.1 kg - 30 kg) / (1947.5 kg - 30 kg) = 0.6

Simplifying this equation:

1155.1 kg / 1917.5 kg = 0.6

Now, let's calculate the weight that needs to be removed from the front.

Let x be the weight to be removed from the front.

762.4 kg - x kg = 0.4 * (1917.5 kg - 30 kg)

Simplifying this equation:

762.4 kg - x kg = 0.4 * 1887.5 kg

762.4 kg - x kg = 754.5 kg

x kg = 762.4 kg - 754.5 kg

x kg = 7.9 kg

Therefore, you need to remove 30 kg from the back and 7.9 kg from the front to maintain a 60% weight distribution in the back.

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Chatgpt says otherwise

burnt pumice
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You took 2/5 of 1887.5

pure kestrel
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But something is wrong infact

burnt pumice
pure kestrel
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something isnt making sense

burnt pumice
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1917.5 x 0.6 = 1150.5

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That’s not how it works

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You can’t subtract from both sides to maintain a constant ratio

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It’s like saying

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8/1

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= 8-4/1-4

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= -4/3

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Is 8 equal to -4/3?

pure kestrel
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So I had to add 4.6kg to the front.
Remove 30kg from the back.
Which resulted in 60% in the back and 40% in the front.

pure kestrel
burnt pumice
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More

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From the back

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Whatever you are adding to the front

pure kestrel
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Assuming I removed 30kg

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What would I need to add to the front

burnt pumice
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Well you have 1917.5 kg

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What is 762.4 / 1917.5

pure kestrel
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0.39760104302

burnt pumice
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Yea

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But there is an exact 40%

pure kestrel
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Wiat

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Wait

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It doesnt matter

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aslong as its 60% in the back

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I dont have to do anything right?

pure kestrel
burnt pumice
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Right now 60.24

pure kestrel
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So in the back its 60.24%

burnt pumice
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Is approx on the back

pure kestrel
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Good

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Then there is no issue

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I am super satisfied

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truly