#Need an idea that doesn't involve intense calculation (or multiplying all of the parenthesis)

26 messages · Page 1 of 1 (latest)

maiden gull
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@frail crow

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Still need help?

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Take a look and see if you can set any of the subtraction to 0

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For example f(1)

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1-1= 0

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So the multiplication is all zero

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Yup

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Yea

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Then just add 7

errant depot
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The extension of the product rule to multiple functions runs like so: (fgh)' = (f(gh))' = f'(gh) + f(gh)' = f'gh + f(g'h + gh') = f'gh + fg'h + fgh'
So if you take the derivative, all but the one specific term that contains (x - 8)' will include (x - 8), meaning it goes to 0 at x = 8.

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...no.

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Did you not see what I said?

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...what's the derivative of x - 8?

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Which means that there is a term here that does not contain (x - 8), because it contains (x - 8)' = 1.

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And what term would that be?

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...almost.

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Right.

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So if we plug x = 8 into that, what do we get?

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Right.

frail crow
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That was a wonderful exercise

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👍

errant depot
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You can give me rep by pinging me and saying "thanks", but I don't know if the bot is up.

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Okay, guess it is.

acoustic iglooBOT
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@barren thunder has given 1 rep to @errant depot

maiden gull
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Oh I’m sorry, I did not realize it was calculus

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That’s my fault