help

[simple bramble]

36+27 = 63

"the digits of the number gets reversed"

personally, I'd just trial and error

[idle ore]

x = tens digit
y = units
so x + y = 9
and 10x + y + 27 = 10y + x

27 = 9y - 9x

smth like this ig

3 = y - x

now y = 3+x

put this is in first eqn

x + 3 + x =9

2x=6

x=3

and then y + 3 = 9

so

y = 6

so number becomes

3*

36*

btw 10x + y makes up the number you know 10s digit and units digit so thats why 10x + y

incase u wonder why

ok so

the close

thing

how does it work

well

¯_(ツ)_/¯

who cares

[abstract forge]

3?

hmm

we find p(alpha)

and multiply it with (alpha) ^8

we do same with beta

to get (alpha)^10

so we get eq and subtact

and rearrange

subtracting the eq with alpha and beta we get
a10 - 6.a9 - 2.a8 = 0

a10 - 2.a8 = 6.a9

for finding :- (a10-2.a8)/2.a9 = 6.a9/2.a9 = 3

^^

this is given just to make the "find the value of" part smaller

else they wouldve made the question way longer
"find the value of (α^10-β^10) ....etc