standard vs vertex form word problem

[vagrant oar]

Anyone?

[earnest canyon]

,rotate

[earnest canyon]

assume a=1
x1 = -2+2i sqrt(3)
by using Vieta's formula, we get:
x2 * (-2+2i sqrt(3)) = 12
x2 = 12/(-2+2i sqrt(3))
x2 = 12/2(-1+i sqrt(3))
x2 = 6/(-1+i sqrt(3))
x2 = 6/(i sqrt(3)-1)
multiply by conjugate
x2 = 6(i sqrt(3)+1)/(-3-1)
x2 = 6(i sqrt(3)+1)/-4
x2 = 3(i sqrt(3)+1)/-2
x2 = -(3/2)(i sqrt(3)+1)
x2 = -(3/2)i sqrt(3)-(3/2)
x2 = -(3/2)-(3/2)i sqrt(3)
root form:
y = (x-x1)(x-x2)
substitute the above roots, expand, then simplify to get the standard form
vertex form:
y = a(x-xs)²+ye
xs = -b/2a
ye = (b²-4ac)/-4a

[vagrant oar]

ok,i think i got it thanks