.
#Function Values Derivatives using Table
tall quiver
Why isn't product rule used in 3g(x)
cuz 3 is a constant
ashen gazelle
cuz 3 is a constant
?
tall quiver
?
yes
well you can use the product rule and you'll end up with the same result
but that isn't needed
tall quiver
When I use the product rule I get -18 but this ges -12
let h(x) = 3, then our expression becomes h(x) g(x)
since 3 is a constant, therefore:
h'(x) = 0
using the product rule, the derivative of h(x) g(x) is:
g(x) h'(x) + h(x) g'(x)
= 3 × 0 + 3 × -4
= 0 - 12
= -12
tall quiver
3(-4)+3(-2)
this is wrong
tall quiver
but when getting the derivative of f(x) dont you use the value givne in the tabl...
yes, but I'm calculating the derivative of 3g(x) as you asked
ashen gazelle
I used -4 as my f(x) derivative
3 × -4 + 3 × -2
and you used 0 as the f(x) derivative
3 × 0 + 3 × -4
why didnt u use the derivative from the table
and instead just used 0
I know using 0 is right but i want to understand why
tall quiver
and instead just used 0
cuz h(x) is just equal to 3, and I replaced 3 with h(x) just to avoid confusion, and the derivative of a constant is just 0
ashen gazelle
yeah i know the derivative of a constant is 0 but
ok wait
so ur saying if the problem was
f(x) x g(x)
I get the value of the derivative from the table
but if the problemm is something like
3g(x) I get the derivative of "3" not from the table?
tall quiver
but if the problemm is something like
3g(x) I get the derivative of "3" not from...
even if you wanted to get it from the table, can you? does it exists in the table?
also 3 is just a constant, that's why it isn't listed in the table
ashen gazelle
Im treating 3 as f(x)
is that wrong?
thats why i used the derivative of f(x) from the table
tall quiver
thats why i used the derivative of f(x) from the table
no, you can't do that, cuz f(x) already exists, therefore you need to denote it as another function
g(x) also exists, so you can't use f(x) and g(x), you need to use other like h(x), p(x) etc
which doesn't exists in the table
tall quiver
no, you can't do that, cuz f(x) already exists, therefore you need to denote it ...
and there's no information that says f(x)=3
it's obvious too by seeing the values of f(x) in the table
I mean there's no information which said f(x) is a constant
yes in the table it looks like f(x)=3
but that's only when x=4
whereas f(x)=3 will always return 3 no matter what values of x is