integration by parts

[chilly current]

is this possible to do with integration by parts?

[autumn moat]

1. Wait patiently for a helper to come along.
2. Once someone helps you, say thank you and close the thread with: ```diff
   +close

[chilly current]

the answer is ||B|| but i got a different answer for some reason. anyone know why?

this is what i did but its wrong

if you have an answer, could you ping me? thank you

[pallid plank]

I think the options are all incorrect

[pallid plank]

also here 4/15 ≠ 2/5

[chilly current]

oh right, my bad

[chilly current]

bruh, this is the princeton review book for calc ab lol

i thought this was supposed to be professional

[pallid plank]

I checked your workings repeatedly and I haven't found any mistakes aside from the last line

[chilly current]

they're the same..

idk how but they are the same answers but in different forms

[pine agate]

$\frac{2}{3}x(x+3)^{\frac{3}{2}} - \frac{4}{15}(x+3)^{\frac{5}{2}}$

$\frac{2}{3}(x+3)^{\frac{3}{2}}x - \frac{2}{3}\frac{2}{5}(x+3)^{\frac{3}{2}}(x+3)$

$\frac{2}{3}(x+3)^{\frac{3}{2}}[x - \frac{2}{5}(x+3)]$

$\frac{2}{3}(x+3)^{\frac{3}{2}}[\frac{3x - 6}{5}]$

$2(x+3)^{\frac{3}{2}}[\frac{x-2}{5}]$

$\frac{2}{5}(x+3}
)^{\frac{3}{2}}[x+3 - 5]$

[pallid plank]

yes I did that too and get the exact same result

[pine agate]

So B is right right?

[pallid plank]

I don't see how are they both equal algebraically

[short cloak]

Mark as read
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[pine agate]

$\frac{2}{5}(x+3)^{\frac{3}{2}} [x+3] - 5\frac{2}{5}(x+3)^{\frac{3}{2}}$

[short cloak]

Mark as read

[pine agate]

@pallid plank

[pallid plank]

ohh I didn't think of that

[pine agate]

Hmmm