Improper integral

[strong lagoon]

1. Wait patiently for a helper to come along.
2. Once someone helps you, say thank you and close the thread with: ```diff
   +close

[wanton dune]

Is the answer by any chance 0? I was able to do it with Feynman's trick

$I(t) = \int_0^{\infty} \frac{\ln x}{1 + tx^2} \dd{x}$

[tepid basalt]

NEONPerseus

[wanton dune]

Nvm it's flawed :/

[deep tusk]

+close