Product Problem

[ruby bison]

Hello, I need help with a little problem where I don't have the method. I had to simplify the following product, someone can help me?

[limber gust]

1. Wait patiently for a helper to come along.
2. Once someone helps you, say thank you and close the thread with: ```diff
   +close

[stable harbor]

Simplify each term and you'd see some pattern

[golden owl]

calculate each term and you'll end up with:
(1/2)×(2/3)×(3/4)×...×(2019/2020)
and all the denominator of one fraction and the numerator of the other fraction cancels out each other aside from 1 and 2020, hence the answer is 1/2020

[ruby bison]

I've already seen it, but i was looking to a way to justify this. I found the "raisonnement par récurrence", idk how you sya un English, and got it

But thx

[golden owl]

urwelcome

[grizzled wasp]

+close