I have been stuck on this for while. Thoughts?
#Complex numbers square roots
hard root
bright dustBOT
I have been stuck on this for while. Thoughts?
- Wait patiently for a helper to come along.
- Once someone helps you, say thank you and close the thread with: ```diff
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worldly marlin
Let a+ib be the square root.
And solve for (a+ib)² = 8-15i ?
no
@hard rootuse that for square roots of complex numbers
worldly marlin
what you said is wrong
dry flame
Let a+ib be the square root.
And solve for (a+ib)² = 8-15i ?
finding square roots of complex numbers is a really lengthy process
doesn't work like that
visual vine
what you said is wrong
However you wish
You just posted a picture saying the same thing I said btw
worldly marlin
You just posted a picture saying the same thing I said btw
visual vine
Not my fault if you don't understand
Ah the skull user kids are out of senses yet again
worldly marlin
Not my fault if you don't understand
alr bro 2 ppl are wrong you are right
visual vine
Ok
worldly marlin
yeah be proud
visual vine
Sure
visual vine
I'm just thinking what you'd be like when you realise what I said was just what's in that book
worldly marlin
yumi?
worldly marlin
I'm just thinking what you'd be like when you realise what I said was just what'...
what is written in that book?
tell me
visual vine
.
worldly marlin
wow you just showed me the pic i sent?
visual vine
Yes
worldly marlin
very smart you are sir
spare zinc
bro why not just rewrite it into a polar form. Then do ^0.5 and then write it back.
or am i drunk
spare zinc
thats what im stating, rewrite the cartesian cords or whatever its called to polar cordinates.
if z = a + bi u can rewrite it as z = r e^(angle)i
taking squareroot of this form is easy
worldly marlin
if z = a + bi u can rewrite it as z = r e^(angle)i
that im not sure of for square rooting a complex number
cant say yes or no
spare zinc
where r = sqr(a^2 + b^2) and angle = tan^1(b/a) + k * 2pi
thats trivial, just trivial lmfao i can write u a proof if u want
worldly marlin
thats trivial, just trivial lmfao i can write u a proof if u want
nah its fine lmaoo
spare zinc
So whats left of ur question
worldly marlin
not mine
visual vine
@night canopy mom this mahjong guy clown skull emoting me and trying to humiliate me for no valid reason 
worldly marlin
spare zinc
not mine
😶
cmon man how u need 2 take roots from omplex numbers if u dotn even know their trivial form!?
spare zinc
be proud
u said u were stuck on the question and this threat is meant for ppl who need help so i assume u need help and u ask that question
or u say u need help with that question, bruh cmon its logic for me to think its Your question
night canopy
what
worldly marlin
what
guy think square rooting a complex number is sqrt a+ib
like sqrt 9+i25 = 3+i5
night canopy
that's not what he wrote
worldly marlin
Let a+ib be the square root.
And solve for (a+ib)² = 8-15i ?
?
This also wrong then ig 😢
visual vine
math is not about your opnion
.
visual vine
am I missing something?
No, that's what I meant🤷♂️
worldly marlin
dry flame
I'll solve this and send later
i can give a hint tho by the time i solve
Let 8-5i = a+ib
Square both sides
dry flame
finding 'a' is going to be really complex but yeah that's how it goes
that's why the question is 5 marks
after that a find b
those are your roots
you can take this question as a reference to know how it's going
https://www.shaalaa.com/question-bank-solutions/find-the-square-roots-of-4-3i-modulus-of-a-complex-number_228939
visual vine
It would be simpler if you consider (a+ib)² = 8 -5i . Not that complex
visual vine
finding 'a' is going to be really complex but yeah that's how it goes
Also you're going nowhere with that. When you already considered 8 - 5i = a + ib, you'd only get a = 8, b = -5.
hard root
Bruh I can't understand shit 😭