#ratio easy

26 messages · Page 1 of 1 (latest)

narrow shale
karmic socketBOT
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  1. Wait patiently for a helper to come along.
  2. Once someone helps you, say thank you and close the thread with: ```diff
    +close
narrow shale
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Ping me when if answering

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Pls

turbid briar
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@narrow shale Start from the fact that the two cylinders r similar which means the dimensions of the one are proportional to the dimensions of the other with ratio λ. Basically the dimensions that define a cylinder are its height h and its base radius r. Since the two cylinders are similar hA/hB=rA/rB=λ.

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You know that the (Area of the base of A)= πrA^2 and the (Area of the base of B)=πrB^2 therefore πrA^2/πrB^2=9/25 => (rA/rB)^2=9/25. Use this to find the ratio λ.

narrow shale
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Lemme try

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I don’t get it @turbid briar

turbid briar
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@narrow shale what you don't get?

narrow shale
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I wrote out what you said it I have no idea

turbid briar
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Do you understand what hA, hB, rA, rB represent?

narrow shale
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The height of a.

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The height of b

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Radius of a

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Radius of b

turbid briar
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Ok so then what is λ

narrow shale
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I don’t know

turbid briar
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λ is the ratio between the two cylinders. For example in the case where λ is 2 you can say that cylinder A is two times bigger than cylinder B. This means that the height of cylinder A is two times the height of B and that the radius of A is two times bigger than the radius of B.

narrow shale
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Ight Kk

turbid briar
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Im sorry, i know i could just give you the answer but that way you won't learn anything.

narrow shale
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Ye thank you for that

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You’re a real one

narrow shale
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@turbid briar ye I’m just stuck

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Don’t get it whatsoever