#Position/Velocity Precalculus

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harsh swiftBOT
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  1. Wait patiently for a helper to come along.
  2. Once someone helps you, say thank you and close the thread with: ```diff
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foggy dagger
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find how fast it's going up at the start

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then you can find the parabola of the path

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(y vs time)

pale kite
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so first what u wanna do is name the numbers, so with variables. For example $\theta = 29^\circ$ and $v_0 = 170 ft/s$. This is a classic projectile motion problem and here you wanna use this and for the amount of time in the air: $t = 2g v_{0}sin(\theta)$ and then use this: $\frac{v^{2}sin(2\theta)}{g}$ to find the amount of distance travelled. (don't get ur units wrong)

novel kiteBOT
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madlad-mathemagician

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im confused

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so what formula do i use?

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hello

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?

foggy dagger
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foggy dagger
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sin 29 times 170?

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what do i do after that?

foggy dagger
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can you find an equation for vertical position in terms of time

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this has a uniform acceleration of g downwards

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i dont know

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help

foggy dagger
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it will reach 0 at the top of the object's path

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because that's when it's going neither up nor down

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and that is the halfway point of the time as well

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because the parabola will be symmetrical

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how do u solve it using this?

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help

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please

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anyone?

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what does that represent?

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hello?

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???
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??

foggy dagger
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new question

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right?

foggy dagger
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no like when it hits the ground what is the y value

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0

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foggy dagger
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yes

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so to find the t value when that happens...?

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0= -16t^2 +210 * sin54t?

foggy dagger
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mhm

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then you can solve for t

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and thats the ansewr for a?

foggy dagger
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and that answers the 1st question

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how about the second question?

pale kite
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thank you

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+close