#Position/Velocity Precalculus
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find how fast it's going up at the start
then you can find the parabola of the path
(y vs time)
so first what u wanna do is name the numbers, so with variables. For example $\theta = 29^\circ$ and $v_0 = 170 ft/s$. This is a classic projectile motion problem and here you wanna use this and for the amount of time in the air: $t = 2g v_{0}sin(\theta)$ and then use this: $\frac{v^{2}sin(2\theta)}{g}$ to find the amount of distance travelled. (don't get ur units wrong)
madlad-mathemagician
memorizing formulas smh >:|
how do you find how fast it is going up at the start?
the speed is the hypotenuse of a triangle
can you find an equation for vertical position in terms of time
this has a uniform acceleration of g downwards
the vertical velocity is constantly decreasing at 32.2 ft/sec
it will reach 0 at the top of the object's path
because that's when it's going neither up nor down
and that is the halfway point of the time as well
because the parabola will be symmetrical
what is g?
what does that represent?
hello?
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what is y(t) when it hits the ground
y(t) = -16t^2 + 210 * sin54 +0
right?
no like when it hits the ground what is the y value
0= -16t^2 +210 * sin54t?
and thats the ansewr for a?
and that answers the 1st question
how about the second question?
no u understand them, but im not gonna explain 2 entire formulas right here. Also they are trivial to understand and derive