#idk if that's positive or negative 52/25
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rynite
that's the simplest form, right?
yea I think its right, so when I plug in the numbers, I get it -52/25
but when I plug them into the initial equation (without simplifying) I get 52/25
why tf is that
$\sqrt{m^2}=|m|$, so if $m$ is negative, then $\sqrt{m^2}=-m$
Civil Service Pigeon
so the answer is positive, right?
Yes, the answer should be positive.
okay thanks, I have a similar question, and it's the same thing, I plug the numbers into the initial equation and the output is a positive number, but when plugging it to the *simplified equation the output is negative
@jovial pumice has given 1 rep to @steel cipher
$\frac{n^{1.5}}{m^{0.2}}$
rynite
that's the simplified equation, is this because of the same thing?
Yes, it's the same thing.
oh, positive 2?
the answer I mean
and is the key here if I understand correctly is that if the power is even, the product has to always be positive so we put a | | around the variable?
actually not the power, I meant the index of the radical
$\sqrt[4]{-5}$
that's not valid for example I guess
rynite
I'd like to ask what you mean, @jovial pumice , by 'not valid'...?
I just did a quick online search and found a 4th root calculator because I'm rusty. It showed me that there is a 4th root for -5, which has two components, one real and one imaginary. I had forgotten this.
I hope I am understanding the context of this conversation okay.
It gave, in fact, four answers.
yeah I mean calculating the 4th root of -5 on my calc results in MATH ERROR, this behavior makes sense if I am understanding correctly ๐
oh, didn't know that. thanks!
No problem! Do you want to see the screenshot of the answer I found on that calculator, or would that be cheating?
I guess it's not important, that's cool. I'll talk you later. Glad to help.
Honestly I would just always put the absolute value and then remove it if you can afterward
alr, thanks ๐
@jovial pumice has given 1 rep to @steel cipher
Anything else before I close this?
nope ๐