#Graphing Rational Functions
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Given a rational function f(x)/g(x), a hole exists at x=a when f(a) = 0 and g(a) = 0
Ex: x+3/(x^2-9)
Notice how when x=-3, both the top and bottom are 0, so there is a hole at (-3,_)
so when f(x) is = to 0
Both functions
If only f(x) = 0 then it’s an x-intercept
If only g(x) = 0 then it’s a vertical asymptote
ok but for this one where the degrees of both the numerator and denominator
are the same,
would there ever be a y-int?
Degrees of the polynomial only really matter when doing horizontal asympote
y-intercept is the y-value when x = 0
Plug in 0 for the equation and see what you get
If you get a number, then that number is y-intercept, else it doesn’t exist
so
I thought I plugged in 0 for my hole
which is what I did acc
and it came out as -3/2
however, when I look for a y-intercept in something like mathway, they dont match up
When you plug x=0 into the full equation(not simplified) you would get 0/0 which is undefined, therefore there is no y-intercept
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