#Square tiling problem
31 messages · Page 1 of 1 (latest)
Is pi the first irrational number you tried?
Yeah, that was gonna be what I was gonna say.
We started by showing and doing our best to prove that you couldn't do it if all the squares were the same size.
Are you familiar with the concept of a golden rectangle?
No, enlighten me.
A golden rectangle is a rectangle with aspect ratio 1:phi, where phi is the golden ratio, (1 + sqrt(5))/2.
What makes a golden rectangle significant is that you can divide it into a square and another golden rectangle.
Ok yes I have encountered this before.
Right. Which means that you can divide a golden rectangle into squares forever, getting infinitesimally small.
Yes
In fact, the same is true for any irrational aspect ratio.
Or proves it, depending on what the conjecture is.
No problem.
An interesting video on the problem:https://www.youtube.com/watch?v=ubHVK71F01M
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So you all know the golden (ratio) spiral. But did you know that not only the golden ratio but really every number has such a spiral associated with it? And that...
Could you devide it up in a different way to tile it without going into the loop?
No, you can't. Think about it like this; take a golden rectangle and divide it into the square and the smaller golden rectangle. Now, the square needs to be tiled over, right? But then you divide the second rectangle into a square and the third rectangle, and the second square also needs tiling over, etc. ad infinitum.
The largest square you can use to tile a rectangle is the smallest square that a descent like this one yields.
I was thinking something more along the lines of this.
I think the video said that it's the square with the side length of the greatest common factor of the rectangle side lengths.
(ms paint mockup)
I don't... understand.
Like using a smaller square and other squares to make a rectangle.
It doesn't matter that its a "loop", what matters is that it's an infinitely repeating process.