# Looking for insight on why 4 is mult by 3 in this diff eq. Its a constant so wouldnt dy/dx = -3y ? Its wrong but I wanna see why Im wrong
# $\frac{dy}{dx}$ is $-3C_1e^{-3x}$ That is $-3[C_1e^{-3x}] -12 + 12$ $-3[C_1e^{-3x} + 4] + 12$ $-3y + 12$