Calculus Help Needed ASAP | Mathematics | Page 1

fleet merlin Mar 9, 2023, 12:19 AM

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I was able to find g'(x) and g''(x)

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But i'm confused when it says line tangent to g'(x)

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Does this mean my tangent line equation will be

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y = g'(a) + g''(a) (x - a) with a = pi ?

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@obsidian trench you have any idea?

obsidian trench Mar 9, 2023, 12:30 AM

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yes

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that would be correct

fleet merlin Mar 9, 2023, 12:32 AM

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This is what I have for part a)

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Do you know how I can simplify the last line of g''(x) to become:

obsidian trench Mar 9, 2023, 12:38 AM

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cos(2x)=cos²x-sin²x
expanded out you have:
50sin²(5x)-50cos²(5x)+50cos(5x)
-50(cos²(5x)-sin²(5x)-cos(5x))
-50(cos(10x)-cos(5x))

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@fleet merlin

fleet merlin Mar 9, 2023, 12:39 AM

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wow

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@obsidian trench u r such a legend brother

obsidian trench Mar 9, 2023, 12:39 AM

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no problem

fleet merlin Mar 9, 2023, 12:39 AM

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Do u know if that second derivative is indeed correct?

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Different online calculators were giving different answers

obsidian trench Mar 9, 2023, 12:46 AM

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I got 50sin²(5x)-50cos²(5x)+50cos(5x) as the second derivative

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which is what you got

fleet merlin Mar 9, 2023, 12:48 AM

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yeah

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nice nice

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Thanks a lot!

obsidian trench Mar 9, 2023, 12:48 AM

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np

#Calculus Help Needed ASAP