#I am going mad
130 messages · Page 1 of 1 (latest)
@fleet garden
I dont know how to solve this
answer is 4
is the question framed correctly or there is amistake
@fleet garden
so x+y+z=6 agreed?
it says f(x+y+z)=f(x)f(y)f(z)
Yes
that's not what I wrote
Then
I wrote x+y+z = 6
Fine but how how is x+y+z = 6
if I say f(x) is something
Okay
and then I say f(4) is something else
we substituted x for 4
in that same function
if I say f(x) = x+1
then f(1) is ?
what does f(x+y+z) mean it means f(x) multiplied to f(y) to f(z)
and we are given that f(6) = 64
so we can assume x+y+z = 6 and f(x)f(y)f(z) = 64
I'm just substituting
2
how did you do that
so f(1) = 1+1
Yes
if I say f(1) = 2
and I say f(x) = x+1
can I take 1 from the first equation from the f(1) and say x=1?
and can I take x+1 and say it's equal to 2?
Yes
that's the same thing we're doing here:
f(6) = 64
f(x+y+z) = f(x)f(y)f(z)
I can say what's in the parentheses is equal
x+y+z = 6
and if that's the case, then f(x)f(y)f(z) = 64
What does f(x)f(y)f(z) mean does it mean multiplied
okay?
we know the problem is asking for f(2)
so it would be convenient to have f(2) so we can solve for it
split up the 6 into a sum of 2s
2+2+2 = 6
correct
f(2+2+2) = 64
or f(x+y+z) = f(x)f(y)f(z)
so we can write f(2+2+2) = f(2)f(2)f(2)
agreed?
Yes
we know f(2+2+2) is the same as f(6)
and we know f(6) is 64
so we can write f(2+2+2) = f(6) = 64
and we can write f(2)f(2)f(2) = 64
because f(2)f(2)f(2) is just f(2+2+2) which is f(6)
following?
good
so when something is multiplied with itself 3 times we can write it as something to the power of 3
$aaa = a^3$
Ephesians 2:8-9
okay?
that's what we're doing here
$f(2)f(2)f(2) = (f(2))^3$
Ephesians 2:8-9
but we're not calculating $2^3$
Ephesians 2:8-9
How u know y value and z value and x value it could have been 2 +3+1
we're calculating (f(2))^3
you won't get far with 2+3+1
because you don't know f(3) and f(1)
and you don't need them
you need f(2) which is why you're using it. it's convenient
yeah but you need to find it
you don't need to find f(1)
or f(3)
we're using f(2) because it's actually convenient to find the solution that way
And here f(x) = turns out to be 2^3.2
$(f(2))^3 = 64$
Ephesians 2:8-9
$f(2)f(2)f(2) = 64$ if that's easier
Ephesians 2:8-9
2
,calc 222
Result:
8
no
Then what
I don't know
@fleet garden Don't close this
I'm sleeping
Tired af
I'll come back and sort this
I wont, look at it tomorrow
i understood
Sleep helped 🙂