#I am going mad

130 messages · Page 1 of 1 (latest)

merry quiver
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@fleet garden

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I dont know how to solve this

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answer is 4

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is the question framed correctly or there is amistake

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@fleet garden

fleet garden
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so x+y+z=6 agreed?

merry quiver
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That is not

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In question

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Question says and f(6)

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Does not say f(x+y+z) = 6

fleet garden
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it says f(x+y+z)=f(x)f(y)f(z)

merry quiver
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Yes

fleet garden
merry quiver
fleet garden
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I wrote x+y+z = 6

merry quiver
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What logic

fleet garden
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which we can conclude from f(6) = 64

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f(6) = 64
f(x+y+z)=f(x)f(y)f(z)

merry quiver
fleet garden
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if I say f(x) is something

merry quiver
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Okay

fleet garden
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and then I say f(4) is something else

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we substituted x for 4

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in that same function

merry quiver
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U just did 6 = 64

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F(6)

fleet garden
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if I say f(x) = x+1
then f(1) is ?

merry quiver
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And hit and trial

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Am I right

fleet garden
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what

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we are given that f(x+y+z) = f(x)f(y)f(z)

merry quiver
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what does f(x+y+z) mean it means f(x) multiplied to f(y) to f(z)

fleet garden
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and we are given that f(6) = 64

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so we can assume x+y+z = 6 and f(x)f(y)f(z) = 64

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I'm just substituting

merry quiver
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Explain to me like a 5

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Year old

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You are making it too complex

fleet garden
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if I say f(x) = x+1

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what is f(1)

merry quiver
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2

fleet garden
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how did you do that

merry quiver
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X as 1

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Cmon

fleet garden
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so f(1) = 1+1

merry quiver
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Yes

fleet garden
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if I say f(1) = 2
and I say f(x) = x+1

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can I take 1 from the first equation from the f(1) and say x=1?

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and can I take x+1 and say it's equal to 2?

merry quiver
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Yes

fleet garden
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that's the same thing we're doing here:
f(6) = 64
f(x+y+z) = f(x)f(y)f(z)

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I can say what's in the parentheses is equal

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x+y+z = 6

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and if that's the case, then f(x)f(y)f(z) = 64

merry quiver
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What does f(x)f(y)f(z) mean does it mean multiplied

fleet garden
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yes

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same function multiplied for different values x,y,z

merry quiver
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okay?

fleet garden
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we know the problem is asking for f(2)

merry quiver
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So

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f(2) =

fleet garden
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so it would be convenient to have f(2) so we can solve for it

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split up the 6 into a sum of 2s

merry quiver
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2+2+2 = 6

fleet garden
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correct

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f(2+2+2) = 64

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or f(x+y+z) = f(x)f(y)f(z)

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so we can write f(2+2+2) = f(2)f(2)f(2)

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agreed?

merry quiver
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Yes

fleet garden
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we know f(2+2+2) is the same as f(6)

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and we know f(6) is 64

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so we can write f(2+2+2) = f(6) = 64

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and we can write f(2)f(2)f(2) = 64

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because f(2)f(2)f(2) is just f(2+2+2) which is f(6)

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following?

merry quiver
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Yes

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I am

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@fleet garden

fleet garden
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good

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so when something is multiplied with itself 3 times we can write it as something to the power of 3

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$aaa = a^3$

astral merlinBOT
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Ephesians 2:8-9

merry quiver
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okay?

fleet garden
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that's what we're doing here

merry quiver
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2^3 is not = 64 2^6

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Is

fleet garden
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$f(2)f(2)f(2) = (f(2))^3$

astral merlinBOT
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Ephesians 2:8-9

fleet garden
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but we're not calculating $2^3$

astral merlinBOT
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Ephesians 2:8-9

merry quiver
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How u know y value and z value and x value it could have been 2 +3+1

fleet garden
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we're calculating (f(2))^3

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you won't get far with 2+3+1

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because you don't know f(3) and f(1)

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and you don't need them

merry quiver
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Ok

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Neither I know f(2)

fleet garden
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you need f(2) which is why you're using it. it's convenient

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yeah but you need to find it

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you don't need to find f(1)

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or f(3)

merry quiver
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Ok

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f(x) = x^2

fleet garden
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we're using f(2) because it's actually convenient to find the solution that way

merry quiver
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And here f(x) = turns out to be 2^3.2

fleet garden
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$(f(2))^3 = 64$

astral merlinBOT
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Ephesians 2:8-9

fleet garden
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$f(2)f(2)f(2) = 64$ if that's easier

astral merlinBOT
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Ephesians 2:8-9

fleet garden
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what number multiplied by itself 3 times gives 64

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@merry quiver

merry quiver
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2

fleet garden
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,calc 222

astral merlinBOT
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Result:

8
fleet garden
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no

merry quiver
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Then what

fleet garden
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figure it out

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f(2) is not 2, it's just a function's value for x=2

merry quiver
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I don't know

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@fleet garden Don't close this

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I'm sleeping

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Tired af

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I'll come back and sort this

fleet garden
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I wont, look at it tomorrow

merry quiver
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i understood

fleet garden
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Sleep helped 🙂