Problems with finding inverse function whenever there's a variable in denominator. | Mathematics | Page 1

twilit meadow Mar 8, 2023, 8:55 AM

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Hello, I'm having problems with number 4 and 8.
f(x) = 3/(4-2x)
y = 3/(4-2x)
=> (4-2x) * y = 3
I don't know how I can arrange it to get inverse and the same problems im having with number 8.

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solved 8 but im still stuck on number 4

twilit meadow Mar 8, 2023, 10:06 AM

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Im not sure but is the ans

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4x-3)/8

weary shell Mar 8, 2023, 10:29 AM

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The answer should be (4x-3)/2x

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Let y =3/4-2x

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=> 4y-2yx=3

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=> 2y(2-x)=3

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=> 2-x=3/2y

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=> x=2-3/2y

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=> x=(4y-3)/2y

#Problems with finding inverse function whenever there's a variable in denominator.