#The side lengths of a parallelogram are 6 cm and 16 cm, and the angle between them is 60°.Calculate
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S = AB * BC * cos
It's S=ABxBCxsin
Ohh yeah, my bad
any idea how to find lenghts?
No, it's those lines who cross in parallelogram
AC and BD
Ah u mean diagonals. Use the cosine rule.
c²=a²+b²-2abcosA
Two angles of parallelogram are 60°. Other two would be 120° each
a is 6 and b is 16?
Yes. c would be one of the diagonals. I can't tell which side is which, so angle would 60° for one diagonal and 120° for the other
thank you very much
Np
I have also other task which I don't know how to do and you probably do, could you help me?