#AP calculus MCQ
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I think cuz the particle never moves higher than the origin
for (A), a < 0 and D < 0 so the graph always lie below the x-axis
for(B), a < 0 but D > 0 so there are times which the particle moves higher than the origin (x-axis), hence it's wrong
isn't the origin (0,0)?
or is it y=0
if its y=0 i understand the answer
yes
yes I assume it is
so by "reaches" the origin it doesnt mean touches 0,0? just means to be at the same vertical level of 0,0 which is y=0?
it doesn't matter cuz the particle only moves along the y-axis
along the y axis means it is only ever negative or only ever positive?
only ever negative or 0