Help With This Hard Question | Mathematics | Page 1

dry escarp Mar 4, 2023, 8:33 PM

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How to find the height diff between the diagonal block and vertical block?

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I got around 2.3 but my teacher said it isn't right

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Heres my working out

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1/cos(t) + 1/sin(t) = 20/7 | c
1/cos²(t) + 1/sin²(t) + 1/2sin(t)cos(t) = 400/49
1/sin(2t)=400/49-1/sin²(t)-1/cos²(t)=>
400sin²tcos²t-49sin²t-49cos²t/9sin²tcos²t=>
400sin²tcos²t-49/(49/4 sin²(2t))=>
100(4sin²tcos²t)=>sin²(2t)
1/sin²t = 100sin²(2t)-49/49/4sin²(2t)=>
k = sin (alpha t)=>
1/k = 400k²-196/49k²=>
400k²-49k²-196=0
x=2401+-sqrt(316001)/800```

flat flameBOT Mar 4, 2023, 8:34 PM

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x឵

dry escarp Mar 4, 2023, 8:44 PM

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considering ceva's theorem and the law of sines:

1 = oa/obob/ococ/oa = sin(oba)/sin(oab)sin(ocb)/sin(obc)sin(oac)/sin(oca) =>4sin(t)sin(40°)cos(10°)/sin(80°-t)...

<=results=> 1 = 2 sin(t)(sin 30° + sin 50°)/sin(80°-t) = sin(1+2cos 40°)/sin(80°-t) =>
2 sin t cos 40° = sin(80° - t) - sin (t) => 2(sin 40° - t)cos 40°...

<=results=> t = 40° - t, t = 20°, angle ACB being 50° and equal to angle BAC...

<=results=> Triangle ABC is isosceles.

stuck junco Mar 4, 2023, 8:45 PM

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dry escarp How to find the height diff between the diagonal block and vertical block?

you need a better diagram

dry escarp Mar 4, 2023, 8:46 PM

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its not to scale its all I was given

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ahhh

bronze kindle Mar 4, 2023, 11:31 PM

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this could be a really hard question if phrased differently

orchid beacon Mar 5, 2023, 12:30 AM

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hi

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can someone please help me with my calculus hw

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A fishing boat sets its course at a heading of 187°, with a speed of 40 knots. The water current is flowing FROM a bearing of S62°W, at 18 knots. Determine the resultant velocity and direction of the fishing boat.

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Im really stuck on this question

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